12-16x=12x^2

Solution for 12-16x=12x^2 equation:

12-16x=12x^2

We move all terms to the left:

12-16x-(12x^2)=0

determiningTheFunctionDomain
-12x^2-16x+12=0

a = -12; b = -16; c = +12;
Δ = b2-4ac
Δ = -162-4·(-12)·12
Δ = 832
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{832}=\sqrt{64*13}=\sqrt{64}*\sqrt{13}=8\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-8\sqrt{13}}{2*-12}=\frac{16-8\sqrt{13}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+8\sqrt{13}}{2*-12}=\frac{16+8\sqrt{13}}{-24}
$